leetcode 714. 买卖股票的最佳时机含手续费

我的解题

按照 labuladong 团灭 LeetCode 股票买卖问题 中给出的算法。

#include <bits/stdc++.h>
using namespace std;
class Solution
{
public:
    /**
     * @brief
     * dp[i][0] = max(dp[i-1][0], dp[i-1][1] + prices[i])
     * dp[i][1] = max(dp[i-1][1], dp[i-1][0] - prices[i] - fee)
     *
     * @param prices
     * @return
     */
    int maxProfit(vector<int> &prices, int fee)
    {
        int dp_i_0 = 0, dp_i_1 = numeric_limits<int>::min();
        for (int i = 0; i < prices.size(); ++i)
        {
            dp_i_0 = max(dp_i_0, dp_i_1 + prices[i]);
            dp_i_1 = max(dp_i_1, dp_i_0 - prices[i] - fee);
        }
        return dp_i_0;
    }
};
int main()
{
    int fee = 2;
    vector<int> price { 1, 3, 2, 8, 4, 9 };
    Solution s;
    cout << s.maxProfit(price, fee) << endl;

}
// g++ test.cpp --std=c++11 -pedantic -Wall -Wextra